Question

PROBLEM 4.1
The distance between the electrodes of a conductivity cell is 0.98 cm and area of cross section of the electrode
is 1.3 cm. Calculate the cell constant for the cell.​

Answer 1

Answer:

cell constant is 0.7538cm-1

Explanation:

b=l÷a=0.98÷1.3=0.7538cm^-1

Answer 2

Answer:

b=l/A=0.98/1.3=0.7538 cm^-1