Question

Problem consists of a string of length N and contains only small case alphabets.

It will be followed by Q queries, in which each query will contain an integer P (1<=P<=N) denoting a position within the string.

Mamta's task is to find the alphabet present at that location and determine the number of occurrence of same alphabet preceding the given location P.

Answer 1

Answer:

aj mere friend ńę meko bye bola wo v chlti bus se I very happy

Answer 2

Answer:int main()

{

int Q[100],i,j,count=0;

long int N,Qn;

char s[100],ch;

scanf("%ld",&N);

scanf("%s",s);

scanf("%ld",&Qn);

for(i=0;i<Qn;i++)

{

scanf("%d",&Q[i]);

}

for(i=0;i<Qn;i++)

{

ch=s[Q[i]-1];

count=0;

for(j=0;j<Q[i]-1;j++)

{

if(ch==s[j])

count++;

}

printf("%d",count);

}

return 0;}

Explanation: