problem of circular motion.. please solve it
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shlapy1gaming:
high school
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yes
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Option A)
Initial speed given to mass M at t =0 , is u.
Then ω = u/L, L = radius of circle in which M goes.
MOI of rod = 1/3 m L²
KE total initially = 1/2 (1/3 m L²) ω² + 1/2 M u² = (m + 3 M) u²/6
Increase in PE of the system when the rod just reaches the vertically opposite position ie. , mass M reaches the top point.
= m g L + M g * 2L = gL (m+2m)
We assume that the KE at this position is negligible.
Equate initial KE = change in PE
u² = gL(m+2m)6 /[ m+3m]
Initial speed given to mass M at t =0 , is u.
Then ω = u/L, L = radius of circle in which M goes.
MOI of rod = 1/3 m L²
KE total initially = 1/2 (1/3 m L²) ω² + 1/2 M u² = (m + 3 M) u²/6
Increase in PE of the system when the rod just reaches the vertically opposite position ie. , mass M reaches the top point.
= m g L + M g * 2L = gL (m+2m)
We assume that the KE at this position is negligible.
Equate initial KE = change in PE
u² = gL(m+2m)6 /[ m+3m]
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