Question

Problem of sec 510 in trigonometry
lesson

Answer 1

Answer:

sec510°=sec(3×180°-30°)

=>sec (-30°)= -sec30°

$= \frac{2}{ \sqrt{3} } \\ \\ = \frac{2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{2 \sqrt{3} }{3}$

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