Math, asked by BrainlyAmateh, 3 months ago

Problem solving ang SHOW SOLUTION

1. How many lottery tickets must be purchased to complete all possible combinations of six numbers, each with a possibility of being from 1 to 49?

2. A singer/performer is auditioning for a musical play. If she is required to sing any three of the 7 prepared songs, in how many ways can she make her choice?​

Answers

Answered by amitnrw
0

Given :  A singer/performer is auditioning for a musical play.

she is required to sing any three of the 7 prepared songs,

To Find : how many ways can she make her choice

Solution:

Total Song = 7

Songs to be sing = 3

3 songs out of 7 can be  selected  in  ⁷C₃  ways

= 35

and 3 songs can be sing in 3!  = 6 ways

Hence total number of ways  = 35 * 6  = 210

Another method

1st song can be selected in 7 ways

2nd song can be selected in 6 ways

3rd song can be selected in 5 ways

Total Ways = 7 x 6 x 5  = 210

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Answered by knjroopa
3

Step-by-step explanation:

Given  

  How many lottery tickets must be purchased to complete all possible combinations of six numbers, each with a possibility of being from 1 to 49?

  • So the given numbers or elements cannot be repeated.
  • So we have n = 49, and r = 6
  • So n Cr = n! / r! (n – r)!
  •     49 C6 = 49! / 6! (49 – 6)!
  •                = 49! / 6! x 43!
  •               = 49 x 48 x 47 x 46 x 45 x 44 / 6 x 5 x 4 x 3 x 2 x 1
  •                = 13983816

Reference link will be

https://brainly.ph/question/12730068

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