PROBLEMS
1. The saturation current density of a Ge p-n diode at 27°C is 300 mA/m2 What voltage must be
applied to the diode to yield a forward current density of 6 x 10' A/mº?
(Ans. 0.375 V)
inn Gre dinde has a reverse saturation current of 1.5 uA at 300 K. Obtain the static and
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Answers
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Answer:
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Answered by
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Answer:
ANSWER
Given,
Satured current I
s
=10μA
=10×10
−6
A
=10
−5
A
Potential barriers for germanium diode =0.3
(i) V=R(I+I
s
)
V=0.3[(100×10
−3
)+10
−9
]
V=0.3[
10
1
+
10
1
]
V=0.3
(ii) V=R(I+I
s
)
1×10
−2
=0.3(I+10
−5
)
−10
−5
+
0.3
10
−2
=I
I=0.33.
Explanation:
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