Problems based on Boyle's law, Charle's law and Gas equation: [Contd.)
f] Calculate the temperature which would be required to reduce the volume of a
gas 'X' initially at stp. to half the initial volume if the pressure is reduced
by 30%.
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2
Answer:
let the final temperature be t2
initial volume=X. final volume=X/2
initial pressure=P. final pressure=(100-30)%P
=70P/100
initial temperature=t1. final temperature=t2
Therefore according to Gas equation
V1*P1/t1=V2*P2/t2
X*P/t1=X*70P/2*100*t2
t2*X*P*2*100/X*70P=t1
t2*2*100/70=t1
t2*2.857=t1
t2=t1/2.857
therefore final temperature should be equal to initial temperature by 2.857.
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