Question

Product analysissolve 3a2+4a-3

Answer 1

/* There is a mistake in the question, it must be like this */

$The \: product \: of \: 3a^{2} \:and \:4a^{-3}$

$= (3a^{2}) \times (4a^{-3})$

$= 3 \times 4 \times a^{2} \times a^{-3}$

$= 12 \times a^{2 - 3}$

/* By Exponential Law */

$\boxed{\pink{ a^{m} \times a^{n} = a^{m+n} }}$

$= 12 \times a^{-1}$

$= 12 \times 1$

$\boxed {\blue { \because a^{-1} = \frac{1}{a} }}$

$= \frac{12}{a}$

Therefore.,

$\red{The \: product \: of \: 3a^{2} \:and \:4a^{-3}}$

$\green { = \frac{12}{a} }$

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