Question

Product if zeroes of the polynomial 3x2-9x+8 is:​

Answer 1

Step-by-step explanation:

product of zeroes in quadratic equation is =c/a

c/a = 8/3

Answer 2

We have to find out the product if zeroes of the polynomial 3x2-9x+8 .

3x² - 9x + 8

x = variable,

2= degree

8 = constant term.

The form of quadratic polynomial :- ax² + bx +c

here in the quadratic polynomial:-

3x² - 9x + 8

a = 3

b= (- 9 )

c = 8

Product of zeroes of polynomial = $\frac{c}{a}$

= (constant term ) ÷ (co efficient of x²)

= ( +8) /3

= $\frac{+8}{3}$

Hence Product of zeroes of the polynomial 3x2-9x+8 is ( $\frac{+8}{3}$ )

Ans :- Product of zeroes of the polynomial 3x2-9x+8 is ( $\frac{+8}{3}$ ).

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