Question

product of 1st 10natural numbers is 2 to the power of a × 3 to the power of b × 5to the power of c × 7 to the power of d then find a+b+c+d
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Answer 1

Answer:

The highest power of a number x contained in n is

[n∖x]+[n∖x

2

]+[n∖x

3

]+........tillbecomes0

n=100

x=2

So total power⇒[100∖2]+[100∖4]+[100∖8]+[100∖16]+[100∖32]+[100∖64]

⇒50+25+12+6+3+1=97

Hence, option 'A' is correct.