product of (-2xy)(-3x^3y^2)(-1/6^2y^7)
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5
Answer:
=(-2)(-3)(1/6)(xy)(x^2*y^2)(x^2y^7)
=(x^(1+2+2))*(y^(1+2+7))
=x^5*y^10
Step-by-step explanation:
Answered by
1
Answer:
(-2xy)(-3x^3y^2)(-1/6^2y^7)
= -2xy*9*x^3y^2*1/36 * y^7
= 18xyx^3y^2*1/36 * y^7
= 1/2 *x^4*y^10
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