Math, asked by RahapriyaSubramanian, 6 months ago

product of (-2xy)(-3x^3y^2)(-1/6^2y^7)​

Answers

Answered by thecreator25
5

Answer:

=(-2)(-3)(1/6)(xy)(x^2*y^2)(x^2y^7)

=(x^(1+2+2))*(y^(1+2+7))

=x^5*y^10

Step-by-step explanation:

Answered by lalitnit
1

Answer:

(-2xy)(-3x^3y^2)(-1/6^2y^7)

= -2xy*9*x^3y^2*1/36 * y^7

= 18xyx^3y^2*1/36 * y^7

= 1/2 *x^4*y^10

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