Math, asked by aayuship1110, 3 months ago

Product of 6a2 – 7b + 5ab and 2ab is

(a) 12a3b – 14ab2 + 10ab

(b) 12a3b – 14ab2 + 10a2b2

(c) 6a2 – 7b + 7ab

(d) 12a2b – 7ab2 + 10ab​

Answers

Answered by attarriaan6226
3

Answer:

B). 12a^3b−14ab ^2 +10a ^2b^2

Step-by-step explanation:

2ab(6a^2 −7b+5ab)

= 2ab×6a^2 −2ab×7b+2ab×5ab

=12a^3b−14ab ^2 +10a ^2b^2

Answered by yogitakarnani8401267
1

Answer:

(6*a²) - (7*b) + {(5*a*b) × (2*a*b)}

= (6*a²) - (7*b) + {(5*2)a²b²}

= (10a²b²)

I think none of this

but if I am wrong so sorry.

Step-by-step explanation:

I always hope it will help

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