Question

One root of f(x)= x3 – 9x2 +26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem
O x= 2, x = 3, or x= 4
O x= -2, x= -3, or x= -4
O x = 1, x = 2, x= 3, or x = 13
O x= -1, x= -2, x= -3, or x= -13​

Answer 1

Answer:

x= 2, x = 3, or x= 4

Step-by-step explanation:

x3 – 9x2 +26x-24 = (x-2)(x-7x+12)

= (x-2)(x-3)(x-4)

Answer 2

Answer:

One root of f(x)= x3 – 9x2 +26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem

O x= 2, x = 3, or x= 4

O x= -2, x= -3, or x= -4

O x = 1, x = 2, x= 3, or x = 13

O x= -1, x= -2, x= -3, or x= -13

Step-by-step explanation:

One root of f(x)= x3 – 9x2 +26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem

O x= 2, x = 3, or x= 4

O x= -2, x= -3, or x= -4

O x = 1, x = 2, x= 3, or x = 13

O x= -1, x= -2, x= -3, or x= -13

One root of f(x)= x3 – 9x2 +26x-24 is x = 2. What are all the roots of the function? Use the Remainder Theorem

O x= 2, x = 3, or x= 4

O x= -2, x= -3, or x= -4

O x = 1, x = 2, x= 3, or x = 13

O x= -1, x= -2, x= -3, or x= -13