Question

Product of 8x^3-3x^2 and 4x^2-2x
With explanation

Answer 1

Answer:

product of 8x^3-3x^2 and 4x^2-2x is (2x^3)(8x-3)(2x-1)

Step-by-step explanation:

(8x^3-3x^2)(4x^2-2x) =

(8x^3)(4x^2)-(8x^3)(2x)-(3x^2)(4x^2)+(3x^2)(2x) =

32x^5-16x^4-12x^4+6x^3 = 32x^5-28x^4+6x^3

= 2x^3(16x^2-14x+3) = 2x^3(16x^2-8x-6x+3)

= 2x^3[8x(2x-1)-3(2x-1)] = (2x^3)(8x-3)(2x-1)

hope it helps you

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