Question

Product of diagonal whose area is 414cm square

Answer 1

$\huge{\boxed{ \boxed{\mathbb{ \red{ANSWER}}}}}$

Area of Square : 414 cm^2.

Side^2 = 414

Side = 20.34 cm.

Now Using Pythagoras theorem, we get the diagonal as 20.34√2.

So, product of diagonal = (20.34)^2 ×2

= 818cm.

Answer 2

$\color {red}\huge\bold\star\underline\mathcal{Question:-}$

We have to find product of diagonals ??

$\bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\:Answer}}}}}}}}}}$

We know that, A square has both diagonals equal ,

so, we just have to find $\large\red{\boxed{\sf </strong><strong>(</strong><strong>Diagonal</strong><strong>)</strong><strong>{</strong><strong>^</strong><strong>2</strong><strong>}</strong><strong>}}$

Now , we know that , area of square with respect to diagonal is :----

$area \: \: = \frac{(diagonal)^{2} }{2} \\ \\ \\ 414 \: = \: \frac{(diagonal)^{2} }{2}$

So,

(diagonal)² = $\large\red{\boxed{\sf 828}}$

$\huge\blue{</strong><strong>Thanks</strong><strong>}$