Question

product of first ten natural numbers =2^a×3^b×5^c×7^d then find the value of a+b+c+d plzz explain step by step ​

Answer 1

Answer:

Step-by-step explanation:

1st 10 natural numbers are 1,2,3,4,5,6,7,8,9,10

product=1*2*3*4*5*6*7*8*9*10

             =$1^1*2^1*3^1*2^2*5^1*(2^1*3^1)*7^1*2^3*3^2*(2^1*5^1)$

             $2^8*3^4*5^2*7^1$

a=8

b=4

c=2

d=1

a+b+c+d=15