Question

Product of first ten natural numbers is 2^a×3^b×5^c×7^d then find the value of a+b+c+d

Answer 1

Answer:

15

Step-by-step explanation:

2^a*3^b*5^c*7^d=1*2*3*4*5*6*7*8*9*10 & \\ 2^a*3^b*5^c*7^d =1*2*3*2^2*5*2*3*7*2^3*3^2*2*5\\ 2^a*3^b*5^c*7^d=2^8*3^4*5^2*7^1

so a=8, b=4, c=2 and d=1

a+b+c+d=15

pls mark this as brainliest