Math, asked by ahteshaam86, 11 months ago

product of m and n ,if difference is 16 and sum of their squars is 400 is

Answers

Answered by abhi569
5

Answer:

Product of both the numbers ( m & n ) is 72.

Step-by-step explanation:

Given,

Difference between m and n is 16 { m > n, if both are +ve }, this means m - n = 16

Square on both sides of m - n = 16

= > ( m - n )^2 = 16^2

= > m^2 + n^2 - 2mn = 256

= > 400 - 2mn = 256 { Given, sum of squares is 400 i.e. m^2 + n^2

= > 400 - 256 = 2mn

= > 144 = 2mn

= > 144 / 2 = mn

= > 72 = mn

Hence, product of both the numbers ( m & n ) is 72.

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