product of m and n ,if difference is 16 and sum of their squars is 400 is
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Answer:
Product of both the numbers ( m & n ) is 72.
Step-by-step explanation:
Given,
Difference between m and n is 16 { m > n, if both are +ve }, this means m - n = 16
Square on both sides of m - n = 16
= > ( m - n )^2 = 16^2
= > m^2 + n^2 - 2mn = 256
= > 400 - 2mn = 256 { Given, sum of squares is 400 i.e. m^2 + n^2
= > 400 - 256 = 2mn
= > 144 = 2mn
= > 144 / 2 = mn
= > 72 = mn
Hence, product of both the numbers ( m & n ) is 72.
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