Question

Product of the roots of px2+2ax+r=0

Answer 1

Answer:

Let r1,r2 be the two roots of the given equation. Given that r1r2=13 . Now,

x2+px+12=(x−r1)(x−r2)

x2+px+12=x2+(−r1−r2)x+r1r2

Comparing coefficients we get,

−r1−r2=p and r1r2=12

If r1r2=12 and r1r2=13 , then 3r21=12 implying r1=±2 .

If r1=2 , then r2=6 and p=−r1−r2=−8 .

If r1=−2 , then r2=−6 and p=−r1−r2=8 .

Therefore, p=±8 .

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Answer 2

Answer:

product of roots=(r/p)

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