Question

Product of tour consecutive positive integers is 840.find that
numbers ?​

Answer 1

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Here is ur answer ♥

Let the consecutive numbers are ( x - 2 ) , ( x - 1 ) , x , ( x + 1 ).

According to the question :

Product of the same consecutive numbers = 840

( x - 2 )( x - 1 )( x )( x + 1 ) = 840

x( x - 2 )( x - 1 )( x + 1 ) = 840

( x² - 2x )( x² - 1 ) = 840

x²( x² - 1 ) - 2x( x² - 1 ) = 840

x⁴ - x² - 2x³ + 2x = 840

x⁴ - 2x³ - x² + 2x + 840 = 0

x⁴ + 5x³ - 7x² - 35x² + 34x² + 170x - 168x - 840 = 0

( x + 5 )( x - 6 )( x² - x + 28 ) = 0

x = - 5 or 6

As numbers are positive, x = 6

Therefore,

the four consecutive integers are : 4 , 5 , 6 , 7.




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