Question

Product of two consecutive even integers is 528. represent the situation as quadratic equation

Answer 1

Step-by-step explanation:

Let the 1st even no. be 2n

Then the 2nd is 2n+2

Product of them = 2n(2n+2)

528 = 4n² + 4n

p(x) = 4n² + 4n - 528 = 0

p(x) = ax² + bx + c = 0

On comparing both the equation, we get,

a=4, b=4, c=-528