product of two consecutive terms in an arithmetic sequence is 204.Of the common difference is 5.Find the terms
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Answer:
The two consecutive terms be -17 , -12 (or) 12 ,17
Step-by-step explanation:
let us take the two consecutive term as (a-d) , a
( a-d )x a = 204
a^2 - ad = 204
a^2 - a(5) = 204
a^2 - 5a = 204
a^2 - 5a - 204 = 0
by factorization method,
(a+12)(a-17) = 0
a + 12 = 0 ; a - 17 = 0
a = - 12 ; a = 17
if a = - 12 the two consecutive terms be,
a - d , a
-12 -5, -12
-17 ,-12
if a = 17 the two consecutive term be,
a - d ,a
17 - 5 , 17
12 , 17
Therefore the two consecutive terms be -17 , -12 (or) 12 ,17
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