Question

Professor absentminded has a very peculiar problem, in that he cannot remember numbers larger than 15. However, he tells his wife, i can remember any number up to 100 by remembering the three numbers obtained as remainders when the number is divided by 3, 5 and 7 respectively. For example (2,3,6) is 17. Professor remembers that he had (0,0,4) rupees in the purse, and he paid (3,2,1) rupees to the servant. How much money is left in the purse?​

Answer 1

Answer:

THEN X MAY BE FROM 13,20,27,....76,83,90,97

Step-by-step explanation:

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LET THE AMOUNT HE HAD BE X

IN THE QUESTION IT IS GIVEN THAT WHEN X IS DIVIDED BY 3,5,7 LEAVES REMAINDERS 1,1,6

LETS TAKE THE LAST NUMBER I.E 7

X%7=6...I.E THE NUM IS 7Y+6

POSSIBLE VALUES OF Y ARE FROM 1 TO 13

THEN X MAY BE FROM 13,20,27,....76,83,90,97

THEN DIVIDE THE ABOVE NUMS BY 3 AND 5 THE NUM WHICH LEAVES REMAINDERS 1,1 IS THE REQUIRED NUM

this might look like a big process but you can calculate the num in your mind.