Program to accept an int type value as a parameter and print the square of it if it is more than 120 otherwise print its cube
Answers
Program in Java:
import java.util.*;
public class Main{
public class void main(String args[]){
Scanner sc = new Scanner(System.in);
System.out.println("Enter a int value : ");
int num = sc.nextInt();
if(num>120){
System.out.println("square of "+num+" is "+(num*num));
}else{
System.out.println("cube of "+num+" is "+(num*num*num));
}
}
}
Output-1:
Enter a int value : 120
square of 120 is 14400
Output-2:
Enter a int value : 121
cube of 121 is 1771561
Explanation:
- i took number from the user using Scanner() class and stored it in num variable of int type
- and checked if the number is greater than 120 or not if true i printed the square by multiplying the number itself in print() statement
- if not then i calculated the cube of the number by multiplying the number with itself 3 times
----Hope you understood my program,if you liked it mark as brainliest,it would really help me. :)
Answer:
Here is your answer friends :-
Explanation:
PROGRAM INPUT :-
import java.util.*;
public class Main{
public class void main(String args[]){
Scanner sc = new Scanner(System.in);
System.out.println("Enter a int value : ");
int num = sc.nextInt();
if(num>120){
System.out.println("square of "+num+" is "+(num*num));
}else{
System.out.println("cube of "+num+" is "+(num*num*num));
}
}
}
Hope it help to u