Question

Program to calculate perfect square in a given range

Answer 1

Answer:

// Finding perfect square numbers in a range using Java

import java.io.IOException;

public class SquareNumbersInRange {

public static void main(String[] args) throws IOException {

int starting_number = 1;

int ending_number = 100;

System.out.println("Perfect Numbers between "+starting_number+ " and "+ending_number);

for (int i = starting_number; i <= ending_number; i++) {

int number = i;

int sqrt = (int) Math.sqrt(number);

if (sqrt * sqrt == number) {

System.out.println(number+ " = "+sqrt+"*"+sqrt);

}

}

}

}