Question

program to change the contents of two memory locations​

Answer 1

Answer:

memory locations 2000H and 2001H and place the result in the memory locations 2002H and 2003H.

Example:

(2000H) = C3H

(2001H) = 29H

Result = C3H + A9H = 016CH

(2002H) = 6CH

(2003H) = 01H

Program:

LXI H, 2000H ; HL points to location 2000H

MOV A, M ; Move the contents of 2000H into accumulator

INX H ; HL points to location 2001H

ADD M ; Add the contents of 2001H with the contents of accumulator

INX H ; HL points to location 2002H

MOV M, A ; Store the lower byte of result at 2002H

MVI A, 00H ; Initialize higher byte result with 00H

ADC A ; Add carry in the higher byte result

INX H ; HL points to location 2003H

MOV M, A ; Store the higher byte of result at 2003H

HLT ; Terminate program execution

Answer 2

Answer:

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Explanation:

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