Question

program to check whether the entered number is palindrome or perfect number. (menu driven program)

Answer 1

Answer:import java.util.*;

class MENU

{

public static void main(String arr[])

{

 Scanner sc=new Scanner(System.in);

 int i,n,r=0,d,ch,s=0;

 System.out.println("Enter a number:");

 n=sc.nextInt();

 System.out.println("MENU");

 System.out.println("1.Palindrome Number");

 System.out.println("2.Perfect Number");

 System.out.println("Enter your choice:");

 ch=sc.nextInt();

 switch(ch)

 {

  case 1:

   for(i=n;i>0;i/=10)

   {

    d=i%10;

    r=r*10+d;

   }

   if(r==n)

    System.out.println("Palindrome Number");

   else

    System.out.println("Not a Palindrome Number");

  break;

  case 2:

   for(i=1;i<n;i++)

   {

    if(n%i==0)

    s=s+i;

   }

   if(s==n)

    System.out.println("Perfect Number");

   else

    System.out.println("Not a Perfect Number");

  break;

  default:

   System.out.println("Invalid choice");

Explanation: