Question

progressive wave of frequency 550hz is travelling with a velocity of 360 m/s how far apart are the two points 60 degree out of phase

Answer 1

k = speed/frequency

=> k =360/550

now phase difference = (2∏/k )* path difference

360 = (360/36) * 550 * path difference

distance bewtween two nearest points is = path difference = 6/50 metre