Question

projectile derivation
for +1​

Answer 1

Explanation:

An object is thrown with a velocity vo with an angle θ with horizontal x-axis. The velocity component along X-axis= Vox=Vocosθ The velocity component along Y-axis =voy=v0sinθ At time T=0, no displacement along X-axis and Y-axis. So, xo=0,y0=0.