proof (a+b)whole cube
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Step by step explaination:
We have to prove the following identity:
(a+b)³ = a³ + b³ + 3ab(a+b)
we are considering LHS to get RHS , so that this identity can be proved.
we can write,
(a+b)³=(a+b)×(a+b)×(a+b)
now , we will solve it
=(a+b)×(a+b)×(a+b)
by multiplying any two brackets
=(a²+b²+2ab)(a+b)
by multiplying these brackets with each other
= a³ + b³ + a²b + b²a + 2a²b + 2b²a
= a³ + b³ + 3a²b + 3b²a
= a³ + b³ + 3 (a²b + b²a)
= a³ + b³ + 3ab(a+b)
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