Question

proof Boolen algebra rules​

Answer 1

Answer:

Boolean Algebraic Theorems

De Morgan's Theorem : ...

Transposition Theorem : ...

Proof: RHS = (A + C) (A' + B) = AA' + A'C + AB + CB = 0 + A'C + AB + BC = A'C + AB + BC(A + A') = AB + ABC + A'C + A'BC = AB + A'C = LHS.

Example: AB + BC' + AC = AC + BC'

Step-by-step explanation:

Answer 2

"6a. X • Y = Y • X Commutative Law

7a. X (Y Z) = (X Y) Z = (X Z) Y = X Y Z Associative Law

7b. X + (Y + Z) = (X + Y) + Z = (X + Z) + Y = X + Y + Z Associative Law

8a. X • (Y + Z) = X Y + X Z Distributive Law

9a. X • Y = X + Y de Morgan's Theorem"