proof :if a sum of either pair of opposite angles of cyclic quadrilateral is 180°
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Step-by-step explanation:
Theorem 7: The sum of the either pair of the opposite angles of a cyclic quadrilateral is 180°. (Angles are supplementary). Given: Let ABCD be a cyclic quadrilateral (Fig.) To Proof: The sum of either pair of the opposite angles of a cyclic quadrilateral, is 180°
manannarang1313:
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Hi Sister. Here is your proof☺
Sol : Given : Let ABCD is cyclic quadrilateral
. To prove : ∠A + ∠C = 180° and ∠B + ∠D = 180°.
Construction : join OB and OD.
Proof : ∠BOD = 2 ∠BAD
∠BAD = 1/2∠ BOD
Similarly ∠BCD = 1/2 ∠DOB
∠BAD + ∠BCD =
1/2∠BOD + 1/2 ∠DOB
=1/2(∠ BOD + ∠DOB)
= (1/2)X360° = 180°
Similarly ∠B + ∠D = 180°
❤hope it helps you ❤
Sol : Given : Let ABCD is cyclic quadrilateral
. To prove : ∠A + ∠C = 180° and ∠B + ∠D = 180°.
Construction : join OB and OD.
Proof : ∠BOD = 2 ∠BAD
∠BAD = 1/2∠ BOD
Similarly ∠BCD = 1/2 ∠DOB
∠BAD + ∠BCD =
1/2∠BOD + 1/2 ∠DOB
=1/2(∠ BOD + ∠DOB)
= (1/2)X360° = 180°
Similarly ∠B + ∠D = 180°
❤hope it helps you ❤
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