Question

Proof: In triangle ABC, angle B = 90° & angle A = angle C = 45°
. BC= AB

By Pythagoras theorem,
AB2+ BC2 =?
AB2 +?=AC2 ........ .. (BC = AB)
2AB2=?
AB2=?

..AB = 1 Upon square root 2AC.​

Answer 1

Answer:

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Answer 2

Given:

triangle ABC

angle B = 90° & angle A = angle C = 45°

BC= AB

By Pythagoras theorem,

AB²+ BC² =AC²

AB²+ AB² =AC²      (BC = AB)

2AB²=AC²

$AB=\frac{1}{\sqrt{2AC} }$

Hence its proof