Math, asked by rextoronon4498, 1 year ago

Proof of the sum of any two sides of a triangle is greater than the third side

Answers

Answered by kowsick82
0
yes it is greater than the 3rd number
Answered by Anonymous
3

Given ΔABC, extend BA to D such that AD = AC.

Now in ΔDBC

∠ADC = ∠ACD [Angles opposite to equal sides are equal]

Hence ∠BCD > ∠ BDC

That is BD > BC [The side opposite to the larger (greater) angle is longer]

Þ AB + AD > BC  

∴ AB + AC > BC [Since AD = AC)

Thus sum of two sides of a triangle is always greater than third side.


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