proof of vt- 1/2at ki square
Answers
Answer:
Assume, for the moment, that the initial velocity is zero. (That’s what v is in the equations, the initial velocity.) So you start with zero velocity. After a time t, your velocity is at. (So, for example, if your acceleration is 2 mph ever second, then after 10 seconds your speed will be at = 2 x 10 = 20 mph.
That’s your velocity at the end. Your velocity at the beginning was zero. So for that time period t, your average velocity is the average between 0 and at, that is, your average velocity V = 1/2 at.
If you moved at this average velocity for the time t, then your distance would be
D = V t = (1/2 at) t = 1/2 at^2
That’s the second term of the equation.
If your initial velocity is not zero but v, then you gain distance from both terms, and the distance you go is
D = v t + 1/2 at^2
Of course, this equation can be devised using calculus. But it doesn’t require calculus.Explanation: