Question

proof root 10 is a irrational number​

Answer 1

Step-by-step explanation:

Assume that √10 is rational. Therefore √10 = a/b where a and b are coprime integers. Then: √10 = a/b 10 = a^2/b^2 10b^2 = a^2 2*(5b^2) = a^2 Since a^2 is a multiple of 2, a must also be a multiple of 2 (if you square an even number, you get an even number, but if you square an odd number, you get an odd number).