proof the hyptenuse therume
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In mathematics, the Pythagorean theorem, also known as Pythagoras's theorem, is a relation in Euclidean geometry among the three sides of a right triangle. It states that the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
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In a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides of the triangle.
Now,
In a right triangle, side opposite to the 90° is always the hypotenuse. The square of the side opposite of the 90° in a right triangle is equal to the sum of squares of the other two sides.
Here,
∆ ABC is a right triangle, right angled at B. AC is the hypotenuse of the right ∆ ABC.
So, the square of AC = the sum of the squares of the other two sides AB and BC.
that is, AC² = AB² + BC²
or, hypotenuse (h)² = perpendicular (p) ² + base (b)² [Pythagoras Theorem]
HENCE Proved ..
HOPE IT HELPS YOU.....
Now,
In a right triangle, side opposite to the 90° is always the hypotenuse. The square of the side opposite of the 90° in a right triangle is equal to the sum of squares of the other two sides.
Here,
∆ ABC is a right triangle, right angled at B. AC is the hypotenuse of the right ∆ ABC.
So, the square of AC = the sum of the squares of the other two sides AB and BC.
that is, AC² = AB² + BC²
or, hypotenuse (h)² = perpendicular (p) ² + base (b)² [Pythagoras Theorem]
HENCE Proved ..
HOPE IT HELPS YOU.....
priyanshukumar5:
sorry i can't understand
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