Math, asked by gayatri21021978, 10 days ago

proof the theory, A diagonal of a parallelogram divides it into two triangle are congruent.​

Answers

Answered by dastamoghna300
1

Step-by-step explanation:

In these two triangles, one side and two angles made on this side are equal. Therefore by ASA rule of congruence: △ABC ≅ △ADC. ... Therefore, it is proved that the diagonal of a parallelogram divides it into two congruent triangles and also opposite sides of a parallelogram are equal.

Answered by avanimehra2010
1

Answer:

REF. Image.

consider Δ ABC and Δ ACD

Since the line segments AB+CD are parallel

to each other and AC is a transversal

∠ ACB = ∠ CAD.

AC = AC (common side)

∠CAB = ∠ ACD.

Thus, by ASA criteria

ΔABC ≅ ΔACD

The corresponding part of the congruent

triangle are congruent

AB = CD + AD = BC

Step-by-step explanation:

hope it helps you

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