Proove (at b+c)³- a³-b³-c³ = 3(a+b)(b+c)(c+a)
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(a+b+c)³- a³-b³-c³
=[a³+b³+c³+3(a+b)(b+c)(c+a)]- a³-b³-c³
= 3(a+b)(b+c)(c+a).
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