Science, asked by garvit88, 11 months ago

Proove (at b+c)³- a³-b³-c³ = 3(a+b)(b+c)(c+a)​

Answers

Answered by poojachinta24
2

Answer:

(a+b+c)³- a³-b³-c³

=[a³+b³+c³+3(a+b)(b+c)(c+a)]- a³-b³-c³

= 3(a+b)(b+c)(c+a).

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