Proove C=epsilon not•d upon A
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Explanation:
Since, C=q/V-------(1)
& We know that charge on plates is
Sigma×area. (As sigma =q/A)
&V=E×d
We also know that E field between the plates is sigma /ebsilnot
So, V=sigma×d/ebsilnot
Now,
By putting values of charge &Voltage
We get
C=sigma×area/sigma×d/ebsilnot
So, C=(ebsilnot×A)/d
Hence proved
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