Question

proove that 1 + tan²A = sec²A​

Answer 1

Heya!

Here is ur answer..

To Prove

1+tan²A = sec²A

LHS :

= 1+tan²A

= 1+(sinA/cosA)²

= 1+sin²A/cos²A

= cos²A+sin²A/cos²A

= 1/cos²A

= (1/cosA)²

= sec²A

RHS = sec²A

Therefore, LHS = RHS

Hence proved!

Answer 2

Answer:

LHS =

1 + tan²A

1 + (SinA/ CosA)²

1 + Sin²A / Cos²A

Cos²A + Sin²A/ Cos²A

1 / Cos²A

( 1CosA²)

Sec²A

RHS = Sec²A

LHS= RHS