Proove that SinA.sin(60_A)sin(60+A)=1/4sin 3A
Answers
Answered by
0
Explanation:
sin A×sin(60-A)×sin(60+A)
sinA.sin60.cosA-cos60.sin60.cosA + cos60
.sinA
=1÷4 3sinA-4sin^3A
=1÷4 sin 3A
Answered by
0
Answer:
See the attachment
Attachments:
Similar questions