Question

proove that there is no natural number n for which 6^n ends with digit zero​

Answer 1

Answer:

6^n always ends with a digit 6

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Answer 2

Answer:

Proved.

Step-by-step explanation:

Let us take the example of a number which ends with the digit 0

So, 10 = 2 * 5

100 = 2 * 2 * 5 * 5

Here we note that numbers ending with 0 has 2 and 5 as their prime factors.

Whereas 6^n = (2*3)^n

Does not have 5 as a prime factor.

So it doesn't end with Zero :)