Question

proove the identity cosA(1+cotA)+sinA(1+tanA)=secA+cosecA​

Answer 1

Step-by-step explanation:

{cosA(1+cotA)+sinA(1+tanA)}

{cosA(sinA+cosA/sinA)+sinA(cosA+sinA/cosA)}

[(sinA+cosA){cosA/sinA+sinA/cosA}]

[(sinA+cosA)(1/sinAcosA)]

[sinA/sinAcosA+cosA/sinAcosA]

[1/cosA+1/sinA]

{secA+cosecA}