Propanol zigzag formula tell me now
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Propane, $C_3 H_8 $, is the next member of the alkane family. Conceptually, propane can be viewed as ethane with one methyl substituent. Instead of analyzing both C-C bonds at the same time, it is more convenient to look at a single C-C and generalize the behavior of the remaining methyl group. The Newman projections show that propane has a set of eclipsed and staggered conformations similar to ethane, but with a torsional strain of 3.3 kcal/mol. Each eclipsed conformation now consists of two eclipsed C-H bonds and one C-H eclipsed with a $C-CH_3 $ bond. We can infer that the latter eclipsing interaction has an energetic "cost" of 1.3 kcal/mol. Bear in mind that these energies do not measure electronic repulsion in any absolute sense, but merely provide figures relative to the more stable staggered state.