Propanone is heated with I2 and excess of NaOH solution.
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Answer: It will give Iodoform test. When propanone is heated with I₂ with excess NaOH then it will form iodoform as yellow precipitate as main product.
Ch₃-C-Ch₃ + I₂ + NaOH(excess.) ⇒ ChI₃ (yellow ppt.)
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