Propene on oxidation with diborane in presence of alkaline hydrogen peroxide gives
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propanol is obtained ... First tripropylborane will be formed then in presence of h2o2 will give propanol
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Welcome dear,
● Answer -
Propan-1-ol (CH3-CH2-CH2-OH)
● Explanation -
Propene on reaction with diborane gives tripropyl borane.
6CH3-CH=CH2 + B2H6 ---> 2(CH3-CH2-CH2)3B
Tripropyl borane on oxidation with alkaline hydrogen peroxide gives propan-1-ol.
(CH3-CH2-CH2)3B + 3H2O2 ---> 3CH3-CH2-CH2-OH + 3B(OH)3
Hope this helps you...
● Answer -
Propan-1-ol (CH3-CH2-CH2-OH)
● Explanation -
Propene on reaction with diborane gives tripropyl borane.
6CH3-CH=CH2 + B2H6 ---> 2(CH3-CH2-CH2)3B
Tripropyl borane on oxidation with alkaline hydrogen peroxide gives propan-1-ol.
(CH3-CH2-CH2)3B + 3H2O2 ---> 3CH3-CH2-CH2-OH + 3B(OH)3
Hope this helps you...
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