Chemistry, asked by Nviasjin2552, 9 months ago

propene treated with chlorine and propene treated with chlorine in presence of light explain the difference in product obtained

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Answered by rohtashnain93

4

Answer:

hello what you want to that point

Answered by pooja303417

0

Answer:

The first step of preparation of glycerol with propene involves the chlorination of of propene at 773 K. It results to form allyl chloride.

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