Math, asked by vemahive, 3 months ago

Proper solution :-
A box of weight 100 N is lifted to a height of 10 m above ground. How much potential energy will be stored in the box?​

Answers

Answered by Anonymous
12

Given that,

• Weight = 100 N

• Height = 10 m

\begin{gathered}\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\star\;{\boxed{\sf{\purple{Weight= Mass \times Acceleration }}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: {100 = Mass \times 10 } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: { \dfrac{100}{10} = Mass } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: { Mass = \cancel\dfrac{100}{10} } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf{ Mass = 10 \: kg } \\\\\\\end{gathered}\end{gathered}

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\begin{gathered}\begin{gathered}\dag\;{\underline{\frak{Again}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\star\;{\boxed{\sf{\purple{Potential ~ energy= Mass \times Acceleration \times Hight }}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: {Potential \: energy = 10 \times 10 \times 10 } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf{ Potential \: energy = 1000 \: J } \\\\\\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\sf \: ∴ \: Hence, \: the \: potential \: energy \: is \: 1000 J \\\\\end{gathered}\end{gathered}

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Answered by SweetCharm
15

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Given that,

• Weight = 100 N

• Height = 10 m

\begin{gathered}\begin{gathered}\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\star\;{\boxed{\sf{\purple{Weight= Mass \times Acceleration }}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: {100 = Mass \times 10 } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: { \dfrac{100}{10} = Mass } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf \: { Mass = \cancel\dfrac{100}{10} } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad \quad {:} \implies \sf{ Mass = 10 \: kg } \\\\\\\end{gathered}\end{gathered}

━━━━━━━━━━━━━━━━━━━━

\begin{gathered}\begin{gathered}\dag\;{\underline{\frak{Again}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\star\;{\boxed{\sf{\purple{Potential ~ energy= Mass \times Acceleration \times Hight }}}}\\ \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered} \quad {:} \implies \sf \: {Potential \: energy = 10 \times 10 \times 10 } \\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\qquad  {:} \implies \sf{ Potential \: energy = 1000 \: J } \\\\\\\end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\sf \: ∴ \: Hence, \: the \: potential \: energy \: is \: 1000 J \\\\\end{gathered}\end{gathered}

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