Protons in the nucleus are of the order of 10−15m (1 fm) apart.
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Question is incomplete ,
Complete question is -----> Protons in the nucleus are of the order of 10−15m(1 fm) apart.What is the magnitude of the electric field produced by a proton at a distance of 3.50 fm from it?
solution :- we know, proton and nucleus both are same nature charged particles.
That's why they repel each other by creating electric field .
Use formula,
where K is kappa constant , K = 9 × 10⁹ Nm²/C²
Q = 1.6 × 10⁻¹⁹ C , r = 3.50 fm = 3.5 × 10⁻¹⁵ m [ 1fm = 10⁻¹⁵]
E = 9 × 10⁹ × 1.6 × 10⁻¹⁹/(3.5)² × 10⁻³⁰
= 14.4 × 10⁻¹⁰⁺³⁰/12.25
= 14.4/12.25 × 10²⁰ N/C
= 1.175 × 10²⁰ N/C
Complete question is -----> Protons in the nucleus are of the order of 10−15m(1 fm) apart.What is the magnitude of the electric field produced by a proton at a distance of 3.50 fm from it?
solution :- we know, proton and nucleus both are same nature charged particles.
That's why they repel each other by creating electric field .
Use formula,
where K is kappa constant , K = 9 × 10⁹ Nm²/C²
Q = 1.6 × 10⁻¹⁹ C , r = 3.50 fm = 3.5 × 10⁻¹⁵ m [ 1fm = 10⁻¹⁵]
E = 9 × 10⁹ × 1.6 × 10⁻¹⁹/(3.5)² × 10⁻³⁰
= 14.4 × 10⁻¹⁰⁺³⁰/12.25
= 14.4/12.25 × 10²⁰ N/C
= 1.175 × 10²⁰ N/C
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